When 6.000 moles of glucose are combusted, 16 815 kJ of

When 6.000 moles of glucose are combusted, 16 815 kJ of energy is produced. Which of the following chemical equations represent this process?
Question options:
6C6H12O6(s) + 36O2(g) ->36CO2(g) + 36H2O()          DH = -2802.15 kJ
6C6H12O6(s) + 36O2(g) -> 36CO2(g) + 36H2O()          DH = 16815 kJ
C6H12O6(s) + 6O2(g) -> 6CO2(g) + 6H2O()                 DH = -16815 kJ
C6H12O6(s) + 6O2(g) -> 6CO2(g) + 6H2O()                DH = -2802.15 kJ
all equations are correct